2x^2+4x-6=2(x+3)(x-1)

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Solution for 2x^2+4x-6=2(x+3)(x-1) equation:



2x^2+4x-6=2(x+3)(x-1)
We move all terms to the left:
2x^2+4x-6-(2(x+3)(x-1))=0
We multiply parentheses ..
2x^2-(2(+x^2-1x+3x-3))+4x-6=0
We calculate terms in parentheses: -(2(+x^2-1x+3x-3)), so:
2(+x^2-1x+3x-3)
We multiply parentheses
2x^2-2x+6x-6
We add all the numbers together, and all the variables
2x^2+4x-6
Back to the equation:
-(2x^2+4x-6)
We add all the numbers together, and all the variables
2x^2+4x-(2x^2+4x-6)-6=0
We get rid of parentheses
2x^2-2x^2+4x-4x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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